Vedic Mathematics: Squares of numbers ending in 5

Consider 25^2 Here the number is 25. We have to find out the square of the number. For the number 25, the last digit is 5 and the ‘previous’ digit is 2. Hence, ‘one more than the previous one’, i.e. 2+1=3. The formula, in this context, gives the procedure to multiply the previous digit 2 by one more than it self, that is, by 3.

It becomes the L.H.S (left hand side) of the result.

i.e. 2 X 3 = 6.

The R.H.S (right hand side) of the result is 5^2, that is, 25.

Thus,

25^2 = 2*(2+1) and 25 = 625

In the same way,

35^2 = 3*(3+1) and 25 = 3*4 and 25 = 1225

65^2 = 6*(6+1) and 25 = 6*7 and 25 = 4225

105^2 = 10*(10+1) and 25 = 10*11 and 25 = 11025

135^2 = 13*(13+1) and 25 = 13*14 and 25 = 18225

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